Sample Solution
library('wooldridge')
data('wage1')
?wage1
#1)
mean(wage1$educ)
min(wage1$educ)
max(wage1$educ)
#2)
mean(wage1$wage)
#This seems low
#3)
#page 259 of the report
#CPI in 1976 is 56.9
#CPI in 2010 is 218.056
#4)
mean(wage1$wage)*218.056/56.9
#5)
nrow(wage1[wage1$female == 1, ])
nrow(wage1[wage1$female == 0, ])
#another possibility
summary(wage1$female==1)